Dextrin

If you find any inaccurate information, please let us know by providing your feedback here

Dextrin

Ước tính: 0 phút đọc, Ngày đăng:
Cập nhật:

This article is compiled based on the United States Pharmacopeia (USP) – 2025 Edition

Issued and maintained by the United States Pharmacopeial Convention (USP)

DOWNLOAD PDF HERE

1 DEFINITION

Dextrin is starch, or partially hydrolyzed starch, modified by heating in a dry state, with or without acids, alkalies, or pH control agents. During heating, moisture may be added.

2 IDENTIFICATION

A.

Sample: 1 g

Analysis:

Suspend the Sample in 20 mL of water, and add a few drops of iodine TS.

Acceptance criteria: A blue to reddish-brown color results.

B. Dextrin is very soluble in boiling water, forming a mucilaginous solution (difference from starch).

3 ASSAY

REDUCING SUGARS (DEXTROSE EQUIVALENT)

Sample: A quantity of Dextrin equivalent to 2.0 g on the dried basis

Analysis: To the Sample add 100 mL of water, shake for 30 min, dilute with water to 200 mL, accurately measured, and filter. To 10.0 mL of alkaline cupric tartrate TS add 20.0 mL of the filtrate, mix, and heat on a hot plate adjusted to bring the solution to a boil in 3 min. Boil for 2 min, and cool quickly. Add 5 mL of potassium iodide solution (3 in 10) and 10 mL of 2N sulfuric acid, mix, and titrate immediately with 0.1 N sodium thiosulfate VS, using starch TS, added toward the end of the titration, as an indicator. Repeat the procedure beginning with "To 10.0 mL of alkaline cupric tartrate TS" using, in place of the filtrate, 20.0 mL of a solution (1 in 1000) of anhydrous dextrose, accurately prepared. Perform a blank titration. Compare (VV) and (V-V).

Result 1 = (VB-VU)

Result 2 = (VB-VS)

VB = volume of 0.1 N sodium thiosulfate consumed in the titrations of the blank

VU = volume of 0.1 N sodium thiosulfate consumed in the titrations of the Dextrin

VS = volume of 0.1 N sodium thiosulfate consumed in the titrations of the dextrose

Acceptance criteria: (VB-VU) is NMT (VB-VS), corresponding to NMT 10%, calculated as dextrose (C6H12O6).

4 IMPURITIES

RESIDUE ON IGNITION (281): NMT 0.5%

CHLORIDE AND SULFATE, Chloride (221)

Sample: 3.0 g

Control: 2.8 mL of 0.020 N hydrochloric acid in 75 mL of water

Analysis: Dissolve the Sample in 75 mL of boiling water. Cool, dilute with water to 75 mL, and filter if necessary. To 25 mL of this solution and

the Control, add 2 mL of nitric acid and 1 mL of silver nitrate TS.

Acceptance criteria: Any turbidity produced is NMT that of the Control, corresponding to NMT 0.2% of chloride.

LIMIT OF PROTEIN

Sample: 10 g

Analysis: Proceed as directed in Nitrogen Determination 〈461〉, using the Sample instead of 1 g, 60 mL of sulfuric acid instead of 20 mL, and

multiplying the percentage of nitrogen found by 6.25.

Acceptance criteria: NMT 1.0%

5 SPECIFIC TESTS

Acidity

Sample: 10.0 g

Analysis: Add the Sample to 100 mL of 70% alcohol, previously neutralized to phenolphthalein. Shake for 1 h, filter, and titrate 50 mL of the filtrate with 0.10 N sodium hydroxide.

Acceptance criteria: NMT 3.0 mL

Botanic Characteristics

Microscopic: Granules are similar in appearance to the starch from which the Dextrin has been prepared, except that when prepared from

corn starch, many of the granules show concentric striations, and when prepared from potato starch, concentric striations are not clearly

visible; the hilum is frequently bicleft; and a small proportion of the granules are distorted.

Loss on Drying 〈731〉: Dry a sample at a pressure not exceeding 100 mm of mercury at 120° for 4 h: it loses NMT 13.0% of its weight.

6 ADDITIONAL REQUIREMENTS

Packaging and Storage: Preserve in well-closed containers.

vui lòng chờ tin đang tải lên

Vui lòng đợi xử lý......

0 SẢN PHẨM
ĐANG MUA
hotline
0927.42.6789