Aluminum Sesquichlorohydrate
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This article is compiled based on the United States Pharmacopeia (USP) – 2025 Edition
Issued and maintained by the United States Pharmacopeial Convention (USP)
AIy(OH)3y-zClz · nH2O
Aluminum chlorohydroxide.
Aluminum hydroxychloride
CAS RN®: 11097-68-0.
Aluminum Sesquichlorohydrate consists of complex basic aluminum chloride that is polymeric and loosely hydrated and encompasses a range of aluminum-to-chloride atomic ratios between 1.26:1 and 1.90:1. It contains not less than 90.0 percent and not more than 110.0 percent of the labeled amount of anhydrous aluminum sesquichlorohydrate.
Packaging and storage-Preserve in well-closed containers.
Labeling-The label states the content of anhydrous aluminum sesquichlorohydrate.
Identification-A solution (1 in 10) responds to the tests for Aluminum (191), and for Chloride (191).
pH (791): between 3.0 and 5.0, in a solution [15 in 100 (w/w)].
Change to read:
ARSENIC (211), Procedures, Procedure 1 (CN 1-Jun-2023): 2 µg per g.
Limit of iron-Using Aluminum Sesquichlorohydrate instead of Aluminum Chlorohydrate, proceed as directed in the test for Limit of iron under Aluminum Chlorohydrate. The limit is 150 µg per g.
Content of aluminum-Using Aluminum Sesquichlorohydrate instead of Aluminum Chlorohydrate, proceed as directed in the test for Content of aluminum under Aluminum Chlorohydrate. Use the result obtained to calculate the Aluminum/chloride atomic ratio.
Content of chloride-Using Aluminum Sesquichlorohydrate instead of Aluminum Chlorohydrate, proceed as directed in the test for Content of chloride under Aluminum Chlorohydrate. Use the result obtained to calculate the Aluminum/chloride atomic ratio.
Aluminum/chloride atomic ratio-Divide the percentage of aluminum found in the test for Content of aluminum by the percentage of chloride found in the test for Content of chloride, and multiply by 35.453/26.98, in which 35.453 and 26.98 are the atomic weights of chlorine and aluminum, respectively: the ratio is between 1.26:1 and 1.90:1.
Assay-Calculate the percentage of anhydrous aluminum sesquichlorohydrate in the Aluminum Sesquichlorohydrate by the formula:
Al({26.98x + [17.01 (3x-1)] +35.453}/26.98x)
in which Al is the percentage of aluminum found in the test for Content of aluminum, x is the aluminum/chloride atomic ratio found in the test for Aluminum/chloride atomic ratio, 26.98 is the atomic weight of aluminum, 17.01 is the molecular weight of the hydroxide anion (OH), and 35.453 is the atomic weight of chlorine (CI).
