Alcohol, 70 Percent, 80 Percent, and 90 Percent
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This article is compiled based on the United States Pharmacopeia (USP) – 2025 Edition
Issued and maintained by the United States Pharmacopeial Convention (USP)
—Prepare by mixing alcohol and water in the proportions given, the measurements being made at 25°.
| Relative Proportions | ||||
| Percent by Volume of C2H5OH at15.56° | SpecificGravityat 25° | Alcohol,mL | Water,mL | Volume inmL of Alcohol, 94.9% v/v, Required for 100 mL |
| 70 | 0.884 | 38.6 | 15 | 73.7 |
| 80 | 0.857 | 45.5 | 9.5 | 84.3 |
| 90 | 0.827 | 51 | 3 | 94.8 |
The proportions of alcohol and water taken to prepare these or any other percentage (v/v) solutions may be determined as follows. Calculate the amount, in mL, of water to be mixed with 100 mL of alcohol taken by the formula:
[94.9(d/c) − 0.8096]100
in which 94.9 is the percentage (v/v) of C H OH in alcohol, 0.8096 is the specific gravity of 94.9% alcohol, d is the specific gravity, obtained from the Alcoholometric Table (see Reference Tables), of the solution containing c% (v/v) of C H OH, and 100 is the volume, in mL, of alcohol taken.
