0.02 N Lithium Methoxide in Methanol VS
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This article is compiled based on the United States Pharmacopeia (USP) – 2025 Edition
Issued and maintained by the United States Pharmacopeial Convention (USP)
CH3LiO, 37.97
759.6 mg in 1000 mL
Dissolve 0.12 g of freshly cut lithium metal in 150 mL of methanol, cooling the flask during addition of the metal. When the reaction is complete, add 850 mL of methanol, and mix. Store the solution preferably in the reservoir of an automatic delivery buret suitably protected from carbon dioxide and moisture.
Standardization: Accurately weigh about 100 mg of primary standard benzoic acid, and dissolve in 80 mL of dimethylformamide in a flask. Add 3 drops of a 1 in 100 solution of thymol blue in dimethylformamide, and titrate with the lithium methoxide solution to a blue endpoint. Correct for the volume of the lithium methoxide solution consumed by 80 mL of the dimethylformamide.
Each 2.442 mg of benzoic acid is equivalent to 1 mL of 0.02 N lithium methoxide. [NOTE-Restandardize the solution frequently.]
N = mg benzoic acid/[122.12 x mL lithium methoxide (corrected for the blank)]
[NOTE-If this volumetric solution is used in a qualitative application such as pH adjustment, dissolution medium, or diluent, its standardization is not required.]
